((2x+x^2)+10)/4)=120

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Solution for ((2x+x^2)+10)/4)=120 equation: 



((2x+x^2)+10)/4)=120

We move all terms to the left:

((2x+x^2)+10)/4)-(120)=0

We multiply all the terms by the denominator


((2x+x^2)+10)=0



We calculate terms in parentheses: +((2x+x^2)+10), so:

(2x+x^2)+10

We get rid of parentheses

x^2+2x+10

Back to the equation:

+(x^2+2x+10)



We get rid of parentheses

x^2+2x+10=0

a = 1; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·1·10
Δ = -36
Delta is less than zero, so there is no solution for the equation

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